If an event E has n(E) equally likely outcomes and it's sample space S has n(S) equally likely outcomes, the probability is
P(E)=n(E)/n(S)
The probability of an event ranges from 0 _< P(E). _< 1
Must occur at 1 but cannot occur at 0
Let's say we were to determine the the probability of drawing a card less than 6 In a 52 card deck.
To solve this we know that there are 5 cards less than six and 4 differente suites for each card.
Therefore the n(E) = 5x4 =20
The total sample space is 52.
So P(of drawing a card less than six) = 20/52=5/13= .38
We can also implement count unprincipled in probability
Let's say we were drawing two marbles from a bag of one green, two yellow, and three red marbles. What is the probability of drawing two yellow marbles?
To determine the sample space, we can use combinations to find the number of outcomes
6C2= 6!/(6-2)!2!=15 total outcomes.
The total number of times we can pick two yellow marbles is 1 because there are only two yellow marbles
Thus
P(E)=.07
Clear and concise, but next time you should use a picture or something.
ReplyDeleteNice Teddy! I always have problems with probability but this has helped me a lot! Thank you! Your explanation is so clear and concise
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